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Complex fresnel using VRayOSLtex
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Beta version released.
Quick presets test (used same glossiness value for all materials (exl. Chromium) only for testing purpose).
Tested with V-Ray 2.x.x, 3.x.x, Corona Renderer 1.x.x, Default Scanline
ComplexFresnel.zip
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Originally posted by Julio_Cayetano View PostWould it be possible to make it to work with Vray RT GPU?
Best regards,
VladoI only act like I know everything, Rogers.
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ComplexFresnel texmap plugin for 3ds Max v.1.0.0 available for download (Free!). Compatible with V-Ray 2.x - 3.x.
http://www.sigerstudio.eu/shop/3ds-m...omplexfresnel/
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For the complex IOR shader (not the artistic shader in the OP), which uses the measured data on refractiveindex.info for n & k you need to input the wavelength in micrometers individually for the R, G and B channels. What is the method used for determining these wavelength values? Here Vlado mentioned R:0.65, G:0.51,B:0.47 (which he said the artist friendly paper used) but on his complex_IOR shader it mentions in the comments the wavelengths R:0.65, G:0.55,B:0.45. So I'm a bit confused as to (1) how to derive these numbers in the first place (2) why the variance?
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The values are the wavelengths of those three values on the visible spectrum. There's a slight amount of variance as "red" can mean a range of hues so I'm not sure if anyone's been as precise as to convert the specific rgb values we're using to exact wavelengths, I'm sure it's possible to do it.
http://science-edu.larc.nasa.gov/EDD...or_Colors.html
Actually here's a converter - http://academo.org/demos/wavelength-...-relationship/
And an explanation saying it's actually kind of hard to do a really accurate conversion between wavelength and hue - http://stackoverflow.com/questions/3...sible-spectrumLast edited by joconnell; 14-07-2015, 09:37 AM.
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So according to the wavelength to RGB calculator (http://academo.org/demos/wavelength-...-relationship/) these are the values for RGB: R:0.645, G:0.51, B:0.44
I notice that the n value for gold in rgb is actually blue (n = 0.18627, 0.75314, 1.4324) rather than yellow. Is this because gold absorbs blue and reflects back yellow?
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Originally posted by sharktacos View PostI notice that the n value for gold in rgb is actually blue (n = 0.18627, 0.75314, 1.4324) rather than yellow. Is this because gold absorbs blue and reflects back yellow?
Best regards,
VladoI only act like I know everything, Rogers.
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