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Direct visible intensity of emitters to low?

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  • Direct visible intensity of emitters to low?

    Hi,

    today I found at VfR 1.05 and 1.5, that colored emitters seems to be limited for direct viewing, the result looks unreal. Here an example - one emitter material intensity 4 and one 444.

    The emitter works better, if I don't use saturated colors. A Red 255,0,0 looks wrong and a light Red like 255,200,200 looks quite good.

    What's going on? How to get a real world look? Is it at 3dsmax the same?

    Regards,
    Micha
    Attached Files
    www.simulacrum.de - visualization for designer and architects

  • #2
    That looks about right. You get the same result in 3ds Max too. I'm not sure what you expect to see... Keep in mind that in nature, usually there are no pure color emitters, there is usually a bit of each component. You can also try to use exponential or Reinhard color mapping with lower Burn value - it will make emitters somewhat more pleasant looking.

    Best regards,
    Vlado
    I only act like I know everything, Rogers.

    Comment


    • #3
      I expect to see a burnout red (mens white) like for half saturated colors like at this example.

      Or is it a problem like digital images are handled? I tested it again and found, if I can play with the frame buffer exposure control and the high intensity emitter stays constant. So, a high intenisty 255,0,0 light source at a HDRI seems not to burn out in every case. Interesting, I expected it would be burn out to a white look.
      Attached Files
      www.simulacrum.de - visualization for designer and architects

      Comment


      • #4
        Originally posted by Micha_cg View Post
        So, a high intenisty 255,0,0 light source at a HDRI seems not to burn out in every case. Interesting, I expected it would be burn out to a white look.
        It will only burn out to white if the other components are different from zero. If you only have red, then red is all you get. It might be possible to implement a color mapping mode similar to the exponential one that will push the color to white as it burns brighter, but we don't have this implemented right now.

        Best regards,
        Vlado
        I only act like I know everything, Rogers.

        Comment

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